What are the solutions to the equation 5x^2+6x=-5 ?

The solutions to the equation 5x^2+6x=-5 are x=-3/5+i 4/5 ,x=-3/5-i 4/5

Find the zeros of 5x^2+6x=-5

The zeros of 5x^2+6x=-5 are x=-3/5+i 4/5 ,x=-3/5-i 4/5

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5 x^{2} + 6 x = - 5

x = - \frac{3}{5} + i \frac{4}{5}, x = - \frac{3}{5} - i \frac{4}{5}

Solution steps

5 x^{2} + 6 x = - 5

Move

5

to the left side

5 x^{2} + 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

Simplify

6^{2} - 4 \cdot 5 \cdot 5 : 8 i

x_{1, 2} = \frac{- 6 \pm 8 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 6 + 8 i}{2 \cdot 5}, x_{2} = \frac{- 6 - 8 i}{2 \cdot 5}

x = \frac{- 6 + 8 i}{2 \cdot 5} : - \frac{3}{5} + i \frac{4}{5}

x = \frac{- 6 - 8 i}{2 \cdot 5} : - \frac{3}{5} - i \frac{4}{5}

The solutions to the quadratic equation are:

x = - \frac{3}{5} + i \frac{4}{5}, x = - \frac{3}{5} - i \frac{4}{5}

y, 2 x - y + 5^{x - 1} = 7 \cdot 5

16 - 4

4 x + 2 = \frac{1}{2} x + 17

7 3^{2}

9 (x + 1)^{2} = 16

What are the solutions to the equation 5x^2+6x=-5 ?
The solutions to the equation 5x^2+6x=-5 are x=-3/5+i 4/5 ,x=-3/5-i 4/5
Find the zeros of 5x^2+6x=-5
The zeros of 5x^2+6x=-5 are x=-3/5+i 4/5 ,x=-3/5-i 4/5