What is (v^2-9*10^{10})(8.35*10^{-28}) ?

The solution to (v^2-9*10^{10})(8.35*10^{-28}) is (167(v^2-9*10^{10}))/(20*10^{28)}

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simplify (v^2-910^{10})(8.3510^{-28})

simplify

(v^{2} - 9 \cdot 1 0^{10}) (8.35 \cdot 1 0^{- 28})

\frac{167 ( v ^{2} - 9 \cdot 1 0 ^{10} )}{20 \cdot 1 0 ^{28}}

Solution steps

(v^{2} - 9 \cdot 1 0^{10}) (8.35 \cdot 1 0^{- 28})

Simplify

8.35 \cdot 1 0^{- 28} : \frac{167}{20 \cdot 1 0 ^{28}}

= (v^{2} - 9 \cdot 1 0^{10}) \frac{167}{20 \cdot 1 0 ^{28}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( v ^{2} - 9 \cdot 1 0 ^{10} ) \cdot 167}{20 \cdot 1 0 ^{28}}

= \frac{167 ( v ^{2} - 9 \cdot 1 0 ^{10} )}{20 \cdot 1 0 ^{28}}

1 0^{- 17} \cdot 0.5

(- 1 - 0.3)^{2} bin o mi o

(7 \cdot 1 0^{a}) \cdot (9 \cdot 1 0^{b})

- x \cdot x + h

- 119.6 e^{- 0.025 \cdot 1}

What is (v^2-9*10^{10})(8.35*10^{-28}) ?
The solution to (v^2-9*10^{10})(8.35*10^{-28}) is (167(v^2-9*10^{10}))/(20*10^{28)}