What are the solutions to the equation 2n^2-10n=10 ?

The solutions to the equation 2n^2-10n=10 are n=(5+3sqrt(5))/2 ,n=(5-3sqrt(5))/2

Find the zeros of 2n^2-10n=10

The zeros of 2n^2-10n=10 are n=(5+3sqrt(5))/2 ,n=(5-3sqrt(5))/2

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2 n^{2} - 10 n = 10

n = \frac{5 + 3 5}{2}, n = \frac{5 - 3 5}{2}

Decimal Notation

n = 5.85410 \dots, n = - 0.85410 \dots

Solution steps

2 n^{2} - 10 n = 10

Move

10

to the left side

2 n^{2} - 10 n - 10 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 (- 10) = 65

n_{1, 2} = \frac{- ( - 10 ) \pm 6 5}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- ( - 10 ) + 6 5}{2 \cdot 2}, n_{2} = \frac{- ( - 10 ) - 6 5}{2 \cdot 2}

n = \frac{- ( - 10 ) + 6 5}{2 \cdot 2} : \frac{5 + 3 5}{2}

n = \frac{- ( - 10 ) - 6 5}{2 \cdot 2} : \frac{5 - 3 5}{2}

The solutions to the quadratic equation are:

n = \frac{5 + 3 5}{2}, n = \frac{5 - 3 5}{2}

4 (3 + \frac{1}{4} c - \frac{1}{2} d)

\frac{10}{5.74} = \frac{x}{2}

t^{- \frac{1}{2}}

3 6^{3}

25 x^{2} + 70 x + 49 = 0

What are the solutions to the equation 2n^2-10n=10 ?
The solutions to the equation 2n^2-10n=10 are n=(5+3sqrt(5))/2 ,n=(5-3sqrt(5))/2
Find the zeros of 2n^2-10n=10
The zeros of 2n^2-10n=10 are n=(5+3sqrt(5))/2 ,n=(5-3sqrt(5))/2