What are the solutions to the equation 25x^2+70x+49=0 ?

The solutions to the equation 25x^2+70x+49=0 are x=-7/5

Find the zeros of 25x^2+70x+49=0

The zeros of 25x^2+70x+49=0 are x=-7/5

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25 x^{2} + 70 x + 49 = 0

x = - \frac{7}{5}

Solution steps

25 x^{2} + 70 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 70 \pm 7 0 ^{2} - 4 \cdot 25 \cdot 49}{2 \cdot 25}

7 0^{2} - 4 \cdot 25 \cdot 49 = 0

x_{1, 2} = \frac{- 70 \pm 0}{2 \cdot 25}

x = \frac{- 70}{2 \cdot 25}

\frac{- 70}{2 \cdot 25} = - \frac{7}{5}

x = - \frac{7}{5}

The solution to the quadratic equation is:

x = - \frac{7}{5}

(a b^{3}) (a^{0} b^{- 2})

a^{2} - a - 20

4 x^{2} - 3 = 11 x

\frac{6 x ^{3} y}{x ^{2}} \cdot \frac{3 x ^{2} y}{8 x ^{3}}

63 x^{2} - 129 x + 36

What are the solutions to the equation 25x^2+70x+49=0 ?
The solutions to the equation 25x^2+70x+49=0 are x=-7/5
Find the zeros of 25x^2+70x+49=0
The zeros of 25x^2+70x+49=0 are x=-7/5