What is expand ln(((y-1)/3)^2) ?

The solution to expand ln(((y-1)/3)^2) is 2(ln(y-1)-ln(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ln(((y-1)/3)^2)

expand

ln ((\frac{y - 1}{3})^{2})

2 (ln (y - 1) - ln (3))

Solution steps

ln ((\frac{y - 1}{3})^{2})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln ((\frac{y - 1}{3})^{2}) = 2 ln (\frac{y - 1}{3})

= 2 ln (\frac{y - 1}{3})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{y - 1}{3}) = ln (y - 1) - ln (3)

= 2 (ln (y - 1) - ln (3))

3 ln (x) + ln (x^{4}) - ln (x^{3} e^{x})

lo g_{4} (16 x^{4} y^{3})

ln (\frac{L ^{5} M ^{2}}{K})

ln (\frac{( x + 2 ) ^{4} y ^{\frac{1}{3}}}{( w - 1 ) ^{3}})

2 ln (x^{- 2}) - ln (y^{2})

What is expand ln(((y-1)/3)^2) ?
The solution to expand ln(((y-1)/3)^2) is 2(ln(y-1)-ln(3))