What are the solutions to the equation 4x^2-3=11x ?

The solutions to the equation 4x^2-3=11x are x=3,x=-1/4

Find the zeros of 4x^2-3=11x

The zeros of 4x^2-3=11x are x=3,x=-1/4

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4 x^{2} - 3 = 11 x

x = 3, x = - \frac{1}{4}

Decimal Notation

x = 3, x = - 0.25

Solution steps

4 x^{2} - 3 = 11 x

Move

11 x

to the left side

4 x^{2} - 3 - 11 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 11 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

(- 11)^{2} - 4 \cdot 4 (- 3) = 13

x_{1, 2} = \frac{- ( - 11 ) \pm 13}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 13}{2 \cdot 4}, x_{2} = \frac{- ( - 11 ) - 13}{2 \cdot 4}

x = \frac{- ( - 11 ) + 13}{2 \cdot 4} : 3

x = \frac{- ( - 11 ) - 13}{2 \cdot 4} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = 3, x = - \frac{1}{4}

\frac{6 x ^{3} y}{x ^{2}} \cdot \frac{3 x ^{2} y}{8 x ^{3}}

63 x^{2} - 129 x + 36

- 8 x + 4 > - 3 x - 31

2 x + 4 < 6 x + 1

(p - 1)^{2} = 6

What are the solutions to the equation 4x^2-3=11x ?
The solutions to the equation 4x^2-3=11x are x=3,x=-1/4
Find the zeros of 4x^2-3=11x
The zeros of 4x^2-3=11x are x=3,x=-1/4