What are the solutions to the equation u^2-4u-5=0 ?

The solutions to the equation u^2-4u-5=0 are u=5,u=-1

Find the zeros of u^2-4u-5=0

The zeros of u^2-4u-5=0 are u=5,u=-1

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u^{2} - 4 u - 5 = 0

u = 5, u = - 1

Solution steps

u^{2} - 4 u - 5 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

u_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, u_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

u = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

u = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

u = 5, u = - 1

a \frac{1}{2} x a^{2}

x^{2} + 13 x + 7 = 0

y^{2} + x^{5} y^{4}

2 x^{2} - 11 x - 6

5 - 6 x = 7 x + 5

What are the solutions to the equation u^2-4u-5=0 ?
The solutions to the equation u^2-4u-5=0 are u=5,u=-1
Find the zeros of u^2-4u-5=0
The zeros of u^2-4u-5=0 are u=5,u=-1