What is 8log_{b}(x)+2log_{b}(z) ?

The solution to 8log_{b}(x)+2log_{b}(z) is log_{b}(x^8z^2)

Popular >

simplify 8log_{b}(x)+2log_{b}(z)

simplify

8 lo g_{b} (x) + 2 lo g_{b} (z)

lo g_{b} (x^{8} z^{2})

Solution steps

8 lo g_{b} (x) + 2 lo g_{b} (z)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

8 lo g_{b} (x) = lo g_{b} (x^{8})

= lo g_{b} (x^{8}) + 2 lo g_{b} (z)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{b} (z) = lo g_{b} (z^{2})

= lo g_{b} (x^{8}) + lo g_{b} (z^{2})

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{b} (x^{8}) + lo g_{b} (z^{2}) = lo g_{b} (x^{8} z^{2})

= lo g_{b} (x^{8} z^{2})

- \frac{2 ln ( 10 x + 5 y - 2 )}{25} + \frac{2 x + y}{5}

ln (6) + ln (3)

ln (4) - ln (\frac{1}{4})

- [\frac{3}{8} lo g_{2} (\frac{3}{8}) + \frac{5}{8} lo g_{2} (\frac{5}{8})]

ln (\frac{( 1 + x ) ^{6} \cdot x}{( 1 + x ) ^{6} - 1})

What is 8log_{b}(x)+2log_{b}(z) ?
The solution to 8log_{b}(x)+2log_{b}(z) is log_{b}(x^8z^2)