What are the solutions to the equation m^2-24=-2m ?

The solutions to the equation m^2-24=-2m are m=4,m=-6

Find the zeros of m^2-24=-2m

The zeros of m^2-24=-2m are m=4,m=-6

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m^{2} - 24 = - 2 m

m = 4, m = - 6

Solution steps

m^{2} - 24 = - 2 m

Move

2 m

to the left side

m^{2} - 24 + 2 m = 0

Write in the standard form

a x^{2} + b x + c = 0

m^{2} + 2 m - 24 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 24) = 10

m_{1, 2} = \frac{- 2 \pm 10}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 2 + 10}{2 \cdot 1}, m_{2} = \frac{- 2 - 10}{2 \cdot 1}

m = \frac{- 2 + 10}{2 \cdot 1} : 4

m = \frac{- 2 - 10}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

m = 4, m = - 6

5 (x - 3) + 8 x = 6 x - 5 + x

x^{2} + 3 x - \frac{3}{4} = 0

\frac{( x ^{3} e ^{- \frac{1}{y ^{3}}} + 5 y ^{5} ) d}{d x}

3 x^{2} - 4 x

\frac{- 6}{3} - \frac{4}{2 ( - 6 )}

What are the solutions to the equation m^2-24=-2m ?
The solutions to the equation m^2-24=-2m are m=4,m=-6
Find the zeros of m^2-24=-2m
The zeros of m^2-24=-2m are m=4,m=-6