What is 2log_{10}(x)-log_{10}(x+6) ?

The solution to 2log_{10}(x)-log_{10}(x+6) is log_{10}((x^2)/(x+6))

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simplify 2log_{10}(x)-log_{10}(x+6)

simplify

2 lo g_{10} (x) - lo g_{10} (x + 6)

lo g_{10} (\frac{x ^{2}}{x + 6})

Solution steps

2 lo g_{10} (x) - lo g_{10} (x + 6)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{10} (x) = lo g_{10} (x^{2})

= lo g_{10} (x^{2}) - lo g_{10} (x + 6)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (x^{2}) - lo g_{10} (x + 6) = lo g_{10} (\frac{x ^{2}}{x + 6})

= lo g_{10} (\frac{x ^{2}}{x + 6})

- lo g_{10} (6.5 \cdot 1 0^{- 12})

4 lo g_{b} (v) + 3 lo g_{b} (q)

ln (\frac{6}{3.1 4 ^{2}})

ln ∣ z + 4 ∣ + 6 (\frac{1}{5} ln ∣ z - 1 ∣ - \frac{1}{5} ln ∣ z + 4 ∣) + ln ∣ x ∣

\frac{ln ( u ^{2} ) - ln ( u ) + ln ( u )}{ln ( u ^{3} )}

What is 2log_{10}(x)-log_{10}(x+6) ?
The solution to 2log_{10}(x)-log_{10}(x+6) is log_{10}((x^2)/(x+6))