What are the solutions to the equation x-2x^2=8 ?

The solutions to the equation x-2x^2=8 are x= 1/4-i(3sqrt(7))/4 ,x= 1/4+i(3sqrt(7))/4

Find the zeros of x-2x^2=8

The zeros of x-2x^2=8 are x= 1/4-i(3sqrt(7))/4 ,x= 1/4+i(3sqrt(7))/4

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x - 2 x^{2} = 8

x = \frac{1}{4} - i \frac{3 7}{4}, x = \frac{1}{4} + i \frac{3 7}{4}

Solution steps

x - 2 x^{2} = 8

Move

8

to the left side

x - 2 x^{2} - 8 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} + x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) ( - 8 )}{2 ( - 2 )}

Simplify

1^{2} - 4 (- 2) (- 8) : 37 i

x_{1, 2} = \frac{- 1 \pm 3 7 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 3 7 i}{2 ( - 2 )}, x_{2} = \frac{- 1 - 3 7 i}{2 ( - 2 )}

x = \frac{- 1 + 3 7 i}{2 ( - 2 )} : \frac{1}{4} - i \frac{3 7}{4}

x = \frac{- 1 - 3 7 i}{2 ( - 2 )} : \frac{1}{4} + i \frac{3 7}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} - i \frac{3 7}{4}, x = \frac{1}{4} + i \frac{3 7}{4}

b^{2} - 16 b + 64

\frac{7}{8} + \frac{3}{4} \cdot \frac{1}{4}

- 9 t - 4 = 23

64 x^{2} - 16 x + 1 = 0

x (ln (6^{- 1})) = ln (6)

What are the solutions to the equation x-2x^2=8 ?
The solutions to the equation x-2x^2=8 are x= 1/4-i(3sqrt(7))/4 ,x= 1/4+i(3sqrt(7))/4
Find the zeros of x-2x^2=8
The zeros of x-2x^2=8 are x= 1/4-i(3sqrt(7))/4 ,x= 1/4+i(3sqrt(7))/4