What is ln((e^{x^2cos(x)})/(sqrt(2x+4))) ?

The solution to ln((e^{x^2cos(x)})/(sqrt(2x+4))) is x^2cos(x)-ln(sqrt(2x+4))

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simplify ln((e^{x^2cos(x)})/(sqrt(2x+4)))

simplify

ln (\frac{e ^{x^{2} c o s (x)}}{2 x + 4})

x^{2} cos (x) - ln (2 x + 4)

Solution steps

ln (\frac{e ^{x^{2} c o s (x)}}{2 x + 4})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{e ^{x^{2} c o s (x)}}{2 x + 4}) = ln (e^{x^{2} c o s (x)}) - ln (2 x + 4)

= ln (e^{x^{2} c o s (x)}) - ln (2 x + 4)

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln (e^{x^{2} c o s (x)}) = x^{2} cos (x) ln (e)

= x^{2} cos (x) ln (e) - ln (2 x + 4)

x^{2} cos (x) ln (e) = x^{2} cos (x)

= x^{2} cos (x) - ln (2 x + 4)

ln (x + 7) - 2 ln (x - 3) + ln (7)

ln (5) + 1 + ln (y) - 7 ln (x)

ln (\frac{e ^{8}}{19})

lo g_{10} (3) + 2 lo g_{10} (x) - 3 lo g_{10} (y)

lo g_{2} (\frac{1}{\frac{1}{6}})

What is ln((e^{x^2cos(x)})/(sqrt(2x+4))) ?
The solution to ln((e^{x^2cos(x)})/(sqrt(2x+4))) is x^2cos(x)-ln(sqrt(2x+4))