What are the solutions to the equation 2(x+9)^2=40 ?

The solutions to the equation 2(x+9)^2=40 are x=2sqrt(5)-9,x=-2sqrt(5)-9

Find the zeros of 2(x+9)^2=40

The zeros of 2(x+9)^2=40 are x=2sqrt(5)-9,x=-2sqrt(5)-9

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2 (x + 9)^{2} = 40

x = 25 - 9, x = - 25 - 9

Solution steps

2 (x + 9)^{2} = 40

Divide both sides by

2

(x + 9)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 9 = 20 : x = 25 - 9

Solve

x + 9 = - 20 : x = - 25 - 9

The solutions to the quadratic equation are:

x = 25 - 9, x = - 25 - 9

x^{2} + 3 x + \frac{9}{4} = 0

4 a^{3} + 12 a^{2} - 64 a - 192

w + 9 < - 6 w + 3

\frac{240}{5 ^{6}}

x^{2} = - 11 x - 10

What are the solutions to the equation 2(x+9)^2=40 ?
The solutions to the equation 2(x+9)^2=40 are x=2sqrt(5)-9,x=-2sqrt(5)-9
Find the zeros of 2(x+9)^2=40
The zeros of 2(x+9)^2=40 are x=2sqrt(5)-9,x=-2sqrt(5)-9