What are the solutions to the equation x^2+3x+9/4 =0 ?

The solutions to the equation x^2+3x+9/4 =0 are x=-3/2

Find the zeros of x^2+3x+9/4 =0

The zeros of x^2+3x+9/4 =0 are x=-3/2

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x^{2} + 3 x + \frac{9}{4} = 0

x = - \frac{3}{2}

Solution steps

x^{2} + 3 x + \frac{9}{4} = 0

Multiply both sides by

4

4 x^{2} + 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 \cdot 9 = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 4}

x = \frac{- 12}{2 \cdot 4}

\frac{- 12}{2 \cdot 4} = - \frac{3}{2}

x = - \frac{3}{2}

The solution to the quadratic equation is:

x = - \frac{3}{2}

4 a^{3} + 12 a^{2} - 64 a - 192

w + 9 < - 6 w + 3

\frac{240}{5 ^{6}}

x^{2} = - 11 x - 10

2 x^{2} - 5 x - 3 = 0

What are the solutions to the equation x^2+3x+9/4 =0 ?
The solutions to the equation x^2+3x+9/4 =0 are x=-3/2
Find the zeros of x^2+3x+9/4 =0
The zeros of x^2+3x+9/4 =0 are x=-3/2