What are the solutions to the equation 2x^2-5x-3=0 ?

The solutions to the equation 2x^2-5x-3=0 are x=3,x=-1/2

Find the zeros of 2x^2-5x-3=0

The zeros of 2x^2-5x-3=0 are x=3,x=-1/2

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2 x^{2} - 5 x - 3 = 0

x = 3, x = - \frac{1}{2}

Decimal Notation

x = 3, x = - 0.5

Solution steps

2 x^{2} - 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 3) = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 2}

x = \frac{- ( - 5 ) + 7}{2 \cdot 2} : 3

x = \frac{- ( - 5 ) - 7}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 3, x = - \frac{1}{2}

3 x^{2} + 8 x - 2 = 0

x^{2} + 14 x + 43 = 0

3 x^{2} + 2 x + 8 = 0

(4 x + 2)^{2}

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What are the solutions to the equation 2x^2-5x-3=0 ?
The solutions to the equation 2x^2-5x-3=0 are x=3,x=-1/2
Find the zeros of 2x^2-5x-3=0
The zeros of 2x^2-5x-3=0 are x=3,x=-1/2