What is ln(((e^x+1))/((x+1))) ?

The solution to ln(((e^x+1))/((x+1))) is ln(e^x+1)-ln(x+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ln(((e^x+1))/((x+1)))

simplify

ln (\frac{( e ^{x} + 1 )}{( x + 1 )})

ln (e^{x} + 1) - ln (x + 1)

Solution steps

ln (\frac{( e ^{x} + 1 )}{( x + 1 )})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{( e ^{x} + 1 )}{( x + 1 )}) = ln ((e^{x} + 1)) - ln ((x + 1))

= ln (e^{x} + 1) - ln (x + 1)

ln (6) + ln (\frac{e ^{(1.74245)}}{3})

ln (c x) + \frac{x ^{2}}{x ^{2} + y ^{2}}

\frac{81 ln ^{4} ( 2 )}{4} - 4 ln^{4} (2)

4 lo g_{10} (m) + lo g_{10} (n)

- \frac{1}{3} ln (z) + \frac{2}{5} ln (y) - ln (x) + ln (2)

What is ln(((e^x+1))/((x+1))) ?
The solution to ln(((e^x+1))/((x+1))) is ln(e^x+1)-ln(x+1)