What are the solutions to the equation m^2-m+2=0 ?

The solutions to the equation m^2-m+2=0 are m= 1/2+i(sqrt(7))/2 ,m= 1/2-i(sqrt(7))/2

Find the zeros of m^2-m+2=0

The zeros of m^2-m+2=0 are m= 1/2+i(sqrt(7))/2 ,m= 1/2-i(sqrt(7))/2

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m^{2} - m + 2 = 0

m = \frac{1}{2} + i \frac{7}{2}, m = \frac{1}{2} - i \frac{7}{2}

Solution steps

m^{2} - m + 2 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 2 : 7 i

m_{1, 2} = \frac{- ( - 1 ) \pm 7 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 1 ) + 7 i}{2 \cdot 1}, m_{2} = \frac{- ( - 1 ) - 7 i}{2 \cdot 1}

m = \frac{- ( - 1 ) + 7 i}{2 \cdot 1} : \frac{1}{2} + i \frac{7}{2}

m = \frac{- ( - 1 ) - 7 i}{2 \cdot 1} : \frac{1}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

m = \frac{1}{2} + i \frac{7}{2}, m = \frac{1}{2} - i \frac{7}{2}

8 \cdot (11 i + 2)

(x - 0.4)^{2} = - 255.84

x^{3} - 64 y^{3}

(- 3 p + 6)^{3}

\frac{5 i}{2 - 3 i}

What are the solutions to the equation m^2-m+2=0 ?
The solutions to the equation m^2-m+2=0 are m= 1/2+i(sqrt(7))/2 ,m= 1/2-i(sqrt(7))/2
Find the zeros of m^2-m+2=0
The zeros of m^2-m+2=0 are m= 1/2+i(sqrt(7))/2 ,m= 1/2-i(sqrt(7))/2