What are the solutions to the equation 8y=12y^2 ?

The solutions to the equation 8y=12y^2 are y=0,y= 2/3

Find the zeros of 8y=12y^2

The zeros of 8y=12y^2 are y=0,y= 2/3

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8 y = 12 y^{2}

y = 0, y = \frac{2}{3}

Decimal Notation

y = 0, y = 0.66666 \dots

Solution steps

8 y = 12 y^{2}

Move

12 y^{2}

to the left side

8 y - 12 y^{2} = 0

Factor

8 y - 12 y^{2} : - 4 y (3 y - 2)

- 4 y (3 y - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 3 y - 2 = 0

Solve

3 y - 2 = 0 : y = \frac{2}{3}

The solutions to the quadratic equation are:

y = 0, y = \frac{2}{3}

\frac{125}{20}

\frac{22 r ^{3} s ^{2}}{11 r ^{2} s ^{- 3}}

- 2 < 2 x + 1 < 1

3 x (x - 1) = - 17 x^{2} + 2

x^{2} \leq 2 x + 48

What are the solutions to the equation 8y=12y^2 ?
The solutions to the equation 8y=12y^2 are y=0,y= 2/3
Find the zeros of 8y=12y^2
The zeros of 8y=12y^2 are y=0,y= 2/3