What is ln((-1+sin(x))/(2+sin(x))) ?

The solution to ln((-1+sin(x))/(2+sin(x))) is ln(-1+sin(x))-ln(2+sin(x))

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simplify ln((-1+sin(x))/(2+sin(x)))

simplify

ln (\frac{- 1 + sin ( x )}{2 + sin ( x )})

ln (- 1 + sin (x)) - ln (2 + sin (x))

Solution steps

ln (\frac{- 1 + sin ( x )}{2 + sin ( x )})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{- 1 + sin ( x )}{2 + sin ( x )}) = ln (- 1 + sin (x)) - ln (2 + sin (x))

= ln (sin (x) - 1) - ln (sin (x) + 2)

6 (ln (3) - ln (2)) \frac{- 3}{2} + 4

2 lo g_{10} (9 x) - lo g_{8} (2 x - 5)

ln (\frac{0.05}{0.1})

\frac{3 ln ( 2 )}{ln ( \frac{27}{4} )}

ln (\frac{x - \frac{1}{2}}{x})

What is ln((-1+sin(x))/(2+sin(x))) ?
The solution to ln((-1+sin(x))/(2+sin(x))) is ln(-1+sin(x))-ln(2+sin(x))