What is (14*0.89)/(0.58)*ln(1/(1-0.1)) ?

The solution to (14*0.89)/(0.58)*ln(1/(1-0.1)) is -(12.46ln(0.9))/(0.58)

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simplify (140.89)/(0.58)ln(1/(1-0.1))

simplify

\frac{14 \cdot 0.89}{0.58} \cdot ln (\frac{1}{1 - 0.1})

- \frac{12.46 ln ( 0.9 )}{0.58}

Decimal Notation

2.26343 \dots

Solution steps

\frac{14 \cdot 0.89}{0.58} ln (\frac{1}{1 - 0.1})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{1}{1 - 0.1}) = ln (1) - ln (1 - 0.1)

= \frac{14 \cdot 0.89}{0.58} (ln (1) - ln (1 - 0.1))

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{14 \cdot 0.89 ( ln ( 1 ) - ln ( 1 - 0.1 ) )}{0.58}

14 \cdot 0.89 (ln (1) - ln (1 - 0.1)) = 12.46 (ln (1) - ln (0.9))

= \frac{12.46 ( ln ( 1 ) - ln ( 0.9 ) )}{0.58}

Apply log rule:

lo g_{a} (1) = 0

= \frac{12.46 ( - ln ( 0.9 ) + 0 )}{0.58}

12.46 (0 - ln (0.9)) = - 12.46 ln (0.9)

= \frac{- 12.46 ln ( 0.9 )}{0.58}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{12.46 ln ( 0.9 )}{0.58}

3 lo g_{3} (x) + 4 lo g_{3} (y)

lo g_{e} (4 e^{3 x})

ln (\frac{8}{4})

- lo g_{10} (9 \cdot 1 0^{- 3})

\frac{1}{2} lo g_{3} (x) + \frac{1}{3} lo g_{3} (2 x + 9)

What is (14*0.89)/(0.58)*ln(1/(1-0.1)) ?
The solution to (14*0.89)/(0.58)*ln(1/(1-0.1)) is -(12.46ln(0.9))/(0.58)