What is the answer to 63(b-1)+7=7(9b-8) ?

The answer to 63(b-1)+7=7(9b-8) is True for all b

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63(b-1)+7=7(9b-8)

63 (b - 1) + 7 = 7 (9 b - 8)

True for all b

Solution steps

63 (b - 1) + 7 = 7 (9 b - 8)

Expand

63 (b - 1) + 7 : 63 b - 56

Expand

7 (9 b - 8) : 63 b - 56

63 b - 56 = 63 b - 56

Move

56

to the right side

63 b = 63 b

Move

63 b

to the left side

0 = 0

Both sides are equal

True for all b

- \frac{1}{2} (- 2)^{3}

\frac{13 !}{5 ! 8 !}

- 10 x - 10 = - 10 x - 10

16 a - 2 a^{4}

y^{2} + 3 y - 2 = 0

What is the answer to 63(b-1)+7=7(9b-8) ?
The answer to 63(b-1)+7=7(9b-8) is True for all b
Solve for b: 63(b-1)+7=7(9b-8)
The solution is True for all b