What are the solutions to the equation y^2+3y-2=0 ?

The solutions to the equation y^2+3y-2=0 are y=(-3+sqrt(17))/2 ,y=(-3-sqrt(17))/2

Find the zeros of y^2+3y-2=0

The zeros of y^2+3y-2=0 are y=(-3+sqrt(17))/2 ,y=(-3-sqrt(17))/2

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y^{2} + 3 y - 2 = 0

y = \frac{- 3 + 17}{2}, y = \frac{- 3 - 17}{2}

Decimal Notation

y = 0.56155 \dots, y = - 3.56155 \dots

Solution steps

y^{2} + 3 y - 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 2) = 17

y_{1, 2} = \frac{- 3 \pm 17}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 3 + 17}{2 \cdot 1}, y_{2} = \frac{- 3 - 17}{2 \cdot 1}

y = \frac{- 3 + 17}{2 \cdot 1} : \frac{- 3 + 17}{2}

y = \frac{- 3 - 17}{2 \cdot 1} : \frac{- 3 - 17}{2}

The solutions to the quadratic equation are:

y = \frac{- 3 + 17}{2}, y = \frac{- 3 - 17}{2}

4 y^{2} - 2 y - 2 = 0

(\frac{x}{2})^{2}

7 u + 13 = 3 u + 9

\frac{8 2}{2}

- 3 - 2 i x + i x + (x + 2) 2 i = 0

What are the solutions to the equation y^2+3y-2=0 ?
The solutions to the equation y^2+3y-2=0 are y=(-3+sqrt(17))/2 ,y=(-3-sqrt(17))/2
Find the zeros of y^2+3y-2=0
The zeros of y^2+3y-2=0 are y=(-3+sqrt(17))/2 ,y=(-3-sqrt(17))/2