What are the solutions to the equation 6x^2-12x=-3 ?

The solutions to the equation 6x^2-12x=-3 are x=(2+sqrt(2))/2 ,x=(2-sqrt(2))/2

Find the zeros of 6x^2-12x=-3

The zeros of 6x^2-12x=-3 are x=(2+sqrt(2))/2 ,x=(2-sqrt(2))/2

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6 x^{2} - 12 x = - 3

x = \frac{2 + 2}{2}, x = \frac{2 - 2}{2}

Solution steps

6 x^{2} - 12 x = - 3

Move

3

to the left side

6 x^{2} - 12 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 6 \cdot 3}{2 \cdot 6}

(- 12)^{2} - 4 \cdot 6 \cdot 3 = 62

x_{1, 2} = \frac{- ( - 12 ) \pm 6 2}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 2}{2 \cdot 6}, x_{2} = \frac{- ( - 12 ) - 6 2}{2 \cdot 6}

x = \frac{- ( - 12 ) + 6 2}{2 \cdot 6} : \frac{2 + 2}{2}

x = \frac{- ( - 12 ) - 6 2}{2 \cdot 6} : \frac{2 - 2}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 2}{2}, x = \frac{2 - 2}{2}

4 m^{2} - 20 am

\frac{( 2 π ( 149.6 \cdot 1 0 ^{6} ) )}{1}

6 x^{2} + 96 x - 13 = - 13

(- \frac{5}{8}) \cdot (\frac{2}{3})

30 \cdot 10

What are the solutions to the equation 6x^2-12x=-3 ?
The solutions to the equation 6x^2-12x=-3 are x=(2+sqrt(2))/2 ,x=(2-sqrt(2))/2
Find the zeros of 6x^2-12x=-3
The zeros of 6x^2-12x=-3 are x=(2+sqrt(2))/2 ,x=(2-sqrt(2))/2