What is expand 3/2 log_{10}(9x^4) ?

The solution to expand 3/2 log_{10}(9x^4) is 3log_{10}(3)+6log_{10}(x)

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expand 3/2 log_{10}(9x^4)

expand

\frac{3}{2} lo g_{10} (9 x^{4})

3 lo g_{10} (3) + 6 lo g_{10} (x)

Solution steps

\frac{3}{2} lo g_{10} (9 x^{4})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

\frac{3}{2} lo g_{10} (9 x^{4}) = \frac{3}{2} lo g_{10} (9) + \frac{3}{2} lo g_{10} (x^{4})

= \frac{3}{2} lo g_{10} (9) + \frac{3}{2} lo g_{10} (x^{4})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (x^{4}) = 4 lo g_{10} (x)

= \frac{3}{2} lo g_{10} (9) + \frac{3}{2} \cdot 4 lo g_{10} (x)

\frac{3}{2} \cdot 4 lo g_{10} (x) = 6 lo g_{10} (x)

= \frac{3}{2} lo g_{10} (9) + 6 lo g_{10} (x)

\frac{3}{2} lo g_{10} (9) = 3 lo g_{10} (3)

= 3 lo g_{10} (3) + 6 lo g_{10} (x)

0.462 - \frac{0.0592}{2} lo g_{10} (\frac{0.02}{0.2})

ln (\frac{( x ^{2} - 1 )}{x ^{3}})

ln (\frac{1}{θ} \cdot e^{- \frac{1}{θ} \cdot x})

ln (\frac{- 4}{1 + I})

12 (ln ∣ (0) + 2 ∣ - ln ∣ (0) + 3 ∣) + C

What is expand 3/2 log_{10}(9x^4) ?
The solution to expand 3/2 log_{10}(9x^4) is 3log_{10}(3)+6log_{10}(x)