What are the solutions to the equation 7x^2-2x-20=8x^2-15x+20 ?

The solutions to the equation 7x^2-2x-20=8x^2-15x+20 are x=5,x=8

Find the zeros of 7x^2-2x-20=8x^2-15x+20

The zeros of 7x^2-2x-20=8x^2-15x+20 are x=5,x=8

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7 x^{2} - 2 x - 20 = 8 x^{2} - 15 x + 20

x = 5, x = 8

Solution steps

7 x^{2} - 2 x - 20 = 8 x^{2} - 15 x + 20

Move

20

to the left side

7 x^{2} - 2 x - 40 = 8 x^{2} - 15 x

Move

15 x

to the left side

7 x^{2} + 13 x - 40 = 8 x^{2}

Move

8 x^{2}

to the left side

- x^{2} + 13 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 ( - 1 ) ( - 40 )}{2 ( - 1 )}

1 3^{2} - 4 (- 1) (- 40) = 3

x_{1, 2} = \frac{- 13 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 13 + 3}{2 ( - 1 )}, x_{2} = \frac{- 13 - 3}{2 ( - 1 )}

x = \frac{- 13 + 3}{2 ( - 1 )} : 5

x = \frac{- 13 - 3}{2 ( - 1 )} : 8

The solutions to the quadratic equation are:

x = 5, x = 8

9 x^{2} y + 12 x y^{2}

x^{2} + (0.5 x + 11)^{2} = (2 x + 1)^{2}

\frac{3}{2} - x > x

20 r + 60 t

- 8 \leq \frac{- 3 x + 1}{4} \leq 6

What are the solutions to the equation 7x^2-2x-20=8x^2-15x+20 ?
The solutions to the equation 7x^2-2x-20=8x^2-15x+20 are x=5,x=8
Find the zeros of 7x^2-2x-20=8x^2-15x+20
The zeros of 7x^2-2x-20=8x^2-15x+20 are x=5,x=8