What is factor 4x^2+44x+121 ?

The solution to factor 4x^2+44x+121 is (2x+11)^2

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factor 4x^2+44x+121

factor

4 x^{2} + 44 x + 121

(2 x + 11)^{2}

Solution steps

4 x^{2} + 44 x + 121

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 x^{2} = (2 x)^{2}

121 = 1 1^{2}

44 x = 2 \cdot 2 x \cdot 11

= (2 x)^{2} + 2 \cdot 2 x \cdot 11 + 1 1^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(2 x)^{2} + 2 \cdot 2 x \cdot 11 + 1 1^{2} = (2 x + 11)^{2}

= (2 x + 11)^{2}

\frac{( x ^{a + b} ) ^{2} ( y ^{a + b} ) ^{2}}{( x y ) ^{2 a - b}}

25 x^{2} - y^{2} + 4 y - 4

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8^{- 2} q^{3} r^{- 5}

- x - x^{2} - 8 x + 12 < 0