What is factor 25x^2-y^2+4y-4 ?

The solution to factor 25x^2-y^2+4y-4 is (5x+y-2)(5x-y+2)

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factor 25x^2-y^2+4y-4

factor

25 x^{2} - y^{2} + 4 y - 4

(5 x + y - 2) (5 x - y + 2)

Solution steps

25 x^{2} - y^{2} + 4 y - 4

Factor

- y^{2} + 4 y - 4 : - (y - 2)^{2}

= 25 x^{2} - (y - 2)^{2}

Simplify

25 x^{2} : (5 x)^{2}

= (5 x)^{2} - (y - 2)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(5 x)^{2} - (y - 2)^{2} = (5 x + (y - 2)) (5 x - (y - 2))

= (5 x + (y - 2)) (5 x - (y - 2))

Simplify

(5 x + (y - 2)) (5 x - (y - 2)) : (5 x + y - 2) (5 x - y + 2)

= (5 x + y - 2) (5 x - y + 2)

3 x^{2} - 13 x y + 12 y^{2}

8^{- 2} q^{3} r^{- 5}

- x - x^{2} - 8 x + 12 < 0

\frac{- 1}{x} < - 2

y^{2} + 10 y = - 9

What is factor 25x^2-y^2+4y-4 ?
The solution to factor 25x^2-y^2+4y-4 is (5x+y-2)(5x-y+2)