What is ln(sec(2)+tan(2))-ln(cos(2))+c ?

The solution to ln(sec(2)+tan(2))-ln(cos(2))+c is ln(-(-sec(2)-tan(2))/(cos(2)))+c

Popular >

simplify ln(sec(2)+tan(2))-ln(cos(2))+c

simplify

ln (sec (2) + tan (2)) - ln (cos (2)) + c

ln (- \frac{- sec ( 2 ) - tan ( 2 )}{cos ( 2 )}) + c

Solution steps

ln (sec (2) + tan (2)) - ln (cos (2)) + c

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (sec (2) + tan (2)) - ln (cos (2)) = ln (\frac{sec ( 2 ) + tan ( 2 )}{cos ( 2 )})

= ln (\frac{sec ( 2 ) + tan ( 2 )}{cos ( 2 )}) + c

\frac{sec ( 2 ) + tan ( 2 )}{cos ( 2 )} = - \frac{- sec ( 2 ) - tan ( 2 )}{cos ( 2 )}

= ln (- \frac{- sec ( 2 ) - tan ( 2 )}{cos ( 2 )}) + c

3 ln (x) + 5 ln (3) - ln (8)

2 lo g_{b} (z) - \frac{1}{4} lo g_{b} (x) + 3 lo g_{b} (y)

lo g_{b} (\frac{x ^{2} y}{2 ^{3}})

x - 1 + ln (\frac{x - 2}{x + 2})

lo g_{10} (\frac{2 x}{y ^{3}})

What is ln(sec(2)+tan(2))-ln(cos(2))+c ?
The solution to ln(sec(2)+tan(2))-ln(cos(2))+c is ln(-(-sec(2)-tan(2))/(cos(2)))+c