What is (ln(b+2a)-ln(a))k-(a+2b)(a+b) ?

The solution to (ln(b+2a)-ln(a))k-(a+2b)(a+b) is ln((b+2a)/a)k-(a+2b)(a+b)

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simplify (ln(b+2a)-ln(a))k-(a+2b)(a+b)

simplify

(ln (b + 2 a) - ln (a)) k - (a + 2 b) (a + b)

ln (\frac{b + 2 a}{a}) k - (a + 2 b) (a + b)

Solution steps

(ln (b + 2 a) - ln (a)) k - (a + 2 b) (a + b)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (b + 2 a) - ln (a) = ln (\frac{b + 2 a}{a})

= ln (\frac{b + 2 a}{a}) k - (a + 2 b) (a + b)

8 ln (x + 6) - 5 ln (x)

- lo g_{10} (2.17 \cdot 1 0^{- 6})

5 ln (x) + ln (x^{2} + 7) - 9 ln (x + 7)

lo g_{10} (3.436 + 1) - lo g_{10} (1.718)

(0.717) ln (\frac{252}{17})

What is (ln(b+2a)-ln(a))k-(a+2b)(a+b) ?
The solution to (ln(b+2a)-ln(a))k-(a+2b)(a+b) is ln((b+2a)/a)k-(a+2b)(a+b)