What are the solutions to the equation 2+2x-x^2=0 ?

The solutions to the equation 2+2x-x^2=0 are x=1-sqrt(3),x=1+sqrt(3)

Find the zeros of 2+2x-x^2=0

The zeros of 2+2x-x^2=0 are x=1-sqrt(3),x=1+sqrt(3)

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2 + 2 x - x^{2} = 0

x = 1 - 3, x = 1 + 3

Solution steps

2 + 2 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 2 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 2}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 2 = 23

x_{1, 2} = \frac{- 2 \pm 2 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 3}{2 ( - 1 )}, x_{2} = \frac{- 2 - 2 3}{2 ( - 1 )}

x = \frac{- 2 + 2 3}{2 ( - 1 )} : 1 - 3

x = \frac{- 2 - 2 3}{2 ( - 1 )} : 1 + 3

The solutions to the quadratic equation are:

x = 1 - 3, x = 1 + 3

8 a^{2} - 18 b^{2}

x^{2} + (10 - x)^{2} < 52

1 0^{\frac{1}{3}} \cdot 10 0^{\frac{1}{3}}

1 - \frac{8}{5}

2 (x - 3) - 3 (x - 2) = x + 2 - (x - 3)

What are the solutions to the equation 2+2x-x^2=0 ?
The solutions to the equation 2+2x-x^2=0 are x=1-sqrt(3),x=1+sqrt(3)
Find the zeros of 2+2x-x^2=0
The zeros of 2+2x-x^2=0 are x=1-sqrt(3),x=1+sqrt(3)