What is 1/2 ln((|x-1|)/(|x+1|))+C ?

The solution to 1/2 ln((|x-1|)/(|x+1|))+C is 1/2 (ln|x-1|-ln|x+1|)+C

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simplify 1/2 ln((|x-1|)/(|x+1|))+C

simplify

\frac{1}{2} ln (\frac{∣ x - 1 ∣}{∣ x + 1 ∣}) + C

\frac{1}{2} (ln ∣ x - 1 ∣ - ln ∣ x + 1 ∣) + C

Solution steps

\frac{1}{2} ln (\frac{∣ x - 1 ∣}{∣ x + 1 ∣}) + C

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{∣ x - 1 ∣}{∣ x + 1 ∣}) = ln ∣ x - 1 ∣ - ln ∣ x + 1 ∣

= \frac{1}{2} (ln ∣ x - 1 ∣ - ln ∣ x + 1 ∣) + C

ln (\frac{x + 13}{( x - 4 ) ^{3} 2 x + 1})

ln (\frac{1.2}{1.5})

- ln (60 - X) + ln (150 - X)

10 \cdot lo g_{e} (\frac{e - 1}{e})

20 lo g_{10} (0.1) + 20 lo g_{10} (2.4) + 92.45

What is 1/2 ln((|x-1|)/(|x+1|))+C ?
The solution to 1/2 ln((|x-1|)/(|x+1|))+C is 1/2 (ln|x-1|-ln|x+1|)+C