What is 3log_{10}(x)-2log_{10}(x+4) ?

The solution to 3log_{10}(x)-2log_{10}(x+4) is log_{10}((x^3)/((x+4)^2))

Popular >

simplify 3log_{10}(x)-2log_{10}(x+4)

simplify

3 lo g_{10} (x) - 2 lo g_{10} (x + 4)

lo g_{10} (\frac{x ^{3}}{( x + 4 ) ^{2}})

Solution steps

3 lo g_{10} (x) - 2 lo g_{10} (x + 4)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

3 lo g_{10} (x) = lo g_{10} (x^{3})

= lo g_{10} (x^{3}) - 2 lo g_{10} (x + 4)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{10} (x + 4) = lo g_{10} ((x + 4)^{2})

= lo g_{10} (x^{3}) - lo g_{10} ((x + 4)^{2})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (x^{3}) - lo g_{10} ((x + 4)^{2}) = lo g_{10} (\frac{x ^{3}}{( x + 4 ) ^{2}})

= lo g_{10} (\frac{x ^{3}}{( x + 4 ) ^{2}})

ln (2 x + 2) - ln (x + 2)

\frac{19.15}{3219 \cdot 0.02} ln (\frac{1}{1 - 0.9})

ln (3 x) - x (\frac{1}{x})

- lo g_{10} (2.85 \cdot 1 0^{- 2})

\frac{π}{6} ln (5)

What is 3log_{10}(x)-2log_{10}(x+4) ?
The solution to 3log_{10}(x)-2log_{10}(x+4) is log_{10}((x^3)/((x+4)^2))