What is 1/2 ln((cos(x)-1)/(cos(x)+1)) ?

The solution to 1/2 ln((cos(x)-1)/(cos(x)+1)) is 1/2 (ln(cos(x)-1)-ln(cos(x)+1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 1/2 ln((cos(x)-1)/(cos(x)+1))

simplify

\frac{1}{2} ln (\frac{cos ( x ) - 1}{cos ( x ) + 1})

\frac{1}{2} (ln (cos (x) - 1) - ln (cos (x) + 1))

Solution steps

\frac{1}{2} ln (\frac{cos ( x ) - 1}{cos ( x ) + 1})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{cos ( x ) - 1}{cos ( x ) + 1}) = ln (cos (x) - 1) - ln (cos (x) + 1)

= \frac{1}{2} (ln (cos (x) - 1) - ln (cos (x) + 1))

ln (\frac{7}{6}) + ln (\frac{5}{6})

9 ln (x + 3) - 2 ln (x)

2 lo g_{10} (tan (1 0^{\circ}) y^{\frac{1}{2}})

- lo g_{10} (1.5 x 1 0^{4})

ln (x e^{7 x})

What is 1/2 ln((cos(x)-1)/(cos(x)+1)) ?
The solution to 1/2 ln((cos(x)-1)/(cos(x)+1)) is 1/2 (ln(cos(x)-1)-ln(cos(x)+1))