What are the solutions to the equation 0=x^2-x-2 ?

The solutions to the equation 0=x^2-x-2 are x=2,x=-1

Find the zeros of 0=x^2-x-2

The zeros of 0=x^2-x-2 are x=2,x=-1

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0 = x^{2} - x - 2

x = 2, x = - 1

Solution steps

0 = x^{2} - x - 2

Switch sides

x^{2} - x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 2) = 3

x_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 1}

x = \frac{- ( - 1 ) + 3}{2 \cdot 1} : 2

x = \frac{- ( - 1 ) - 3}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 2, x = - 1

3343

- 7

\frac{2}{3} - \frac{1}{5}

x^{3} - x^{2} - 5 x + 6

5 x^{2} + 200 = 0

What are the solutions to the equation 0=x^2-x-2 ?
The solutions to the equation 0=x^2-x-2 are x=2,x=-1
Find the zeros of 0=x^2-x-2
The zeros of 0=x^2-x-2 are x=2,x=-1