What are the solutions to the equation x^2+8x=0 ?

The solutions to the equation x^2+8x=0 are x=0,x=-8

Find the zeros of x^2+8x=0

The zeros of x^2+8x=0 are x=0,x=-8

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x^{2} + 8 x = 0

x = 0, x = - 8

Solution steps

x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 \cdot 1}, x_{2} = \frac{- 8 - 8}{2 \cdot 1}

x = \frac{- 8 + 8}{2 \cdot 1} : 0

x = \frac{- 8 - 8}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 0, x = - 8

\frac{6 x - 3}{x - 1} \geq x

2 x^{2} - 5 x + 3 \geq 0

4 - k^{2}

t = 2 (9) + 9

x^{2} + 6 x - 112 = 0

What are the solutions to the equation x^2+8x=0 ?
The solutions to the equation x^2+8x=0 are x=0,x=-8
Find the zeros of x^2+8x=0
The zeros of x^2+8x=0 are x=0,x=-8