What are the solutions to the equation x^2+6x-112=0 ?

The solutions to the equation x^2+6x-112=0 are x=8,x=-14

Find the zeros of x^2+6x-112=0

The zeros of x^2+6x-112=0 are x=8,x=-14

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x^{2} + 6 x - 112 = 0

x = 8, x = - 14

Solution steps

x^{2} + 6 x - 112 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 112 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 112) = 22

x_{1, 2} = \frac{- 6 \pm 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 22}{2 \cdot 1}, x_{2} = \frac{- 6 - 22}{2 \cdot 1}

x = \frac{- 6 + 22}{2 \cdot 1} : 8

x = \frac{- 6 - 22}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

x = 8, x = - 14

h^{2} + 7 h = 44

x^{2} - 3 x = 5

∣ 2 - 16 x ∣ < - 13

4 x^{2} + 19 x - 22 = 0

\frac{( 4 + 4 i )}{( 5 + 4 i )}

What are the solutions to the equation x^2+6x-112=0 ?
The solutions to the equation x^2+6x-112=0 are x=8,x=-14
Find the zeros of x^2+6x-112=0
The zeros of x^2+6x-112=0 are x=8,x=-14