What are the solutions to the equation 9x^2=18x-14 ?

The solutions to the equation 9x^2=18x-14 are x=1+i(sqrt(5))/3 ,x=1-i(sqrt(5))/3

Find the zeros of 9x^2=18x-14

The zeros of 9x^2=18x-14 are x=1+i(sqrt(5))/3 ,x=1-i(sqrt(5))/3

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9 x^{2} = 18 x - 14

x = 1 + i \frac{5}{3}, x = 1 - i \frac{5}{3}

Solution steps

9 x^{2} = 18 x - 14

Move

14

to the left side

9 x^{2} + 14 = 18 x

Move

18 x

to the left side

9 x^{2} + 14 - 18 x = 0

Write in the standard form

a x^{2} + b x + c = 0

9 x^{2} - 18 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 9 \cdot 14}{2 \cdot 9}

Simplify

(- 18)^{2} - 4 \cdot 9 \cdot 14 : 65 i

x_{1, 2} = \frac{- ( - 18 ) \pm 6 5 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6 5 i}{2 \cdot 9}, x_{2} = \frac{- ( - 18 ) - 6 5 i}{2 \cdot 9}

x = \frac{- ( - 18 ) + 6 5 i}{2 \cdot 9} : 1 + i \frac{5}{3}

x = \frac{- ( - 18 ) - 6 5 i}{2 \cdot 9} : 1 - i \frac{5}{3}

The solutions to the quadratic equation are:

x = 1 + i \frac{5}{3}, x = 1 - i \frac{5}{3}

- \frac{6}{5} \cdot 5

21 x^{4} - 114 x^{3} + 45 x^{2}

3^{2} + 8^{2} = x^{2}

2 (3 t - 1) + t = 6 - t

What are the solutions to the equation 9x^2=18x-14 ?
The solutions to the equation 9x^2=18x-14 are x=1+i(sqrt(5))/3 ,x=1-i(sqrt(5))/3
Find the zeros of 9x^2=18x-14
The zeros of 9x^2=18x-14 are x=1+i(sqrt(5))/3 ,x=1-i(sqrt(5))/3