What are the solutions to the equation 3^2+8^2=x^2 ?

The solutions to the equation 3^2+8^2=x^2 are x=sqrt(73),x=-sqrt(73)

Find the zeros of 3^2+8^2=x^2

The zeros of 3^2+8^2=x^2 are x=sqrt(73),x=-sqrt(73)

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3^{2} + 8^{2} = x^{2}

x = 73, x = - 73

Decimal Notation

x = 8.54400 \dots, x = - 8.54400 \dots

Solution steps

3^{2} + 8^{2} = x^{2}

Switch sides

x^{2} = 3^{2} + 8^{2}

Simplify

3^{2} + 8^{2} : 73

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 73, x = - 73

2 (3 t - 1) + t = 6 - t

7 x^{2} + 5 = 12

\frac{3}{a + 1} \geq 3

4 g^{6} h^{6} - 9 j^{6} k^{6}

What are the solutions to the equation 3^2+8^2=x^2 ?
The solutions to the equation 3^2+8^2=x^2 are x=sqrt(73),x=-sqrt(73)
Find the zeros of 3^2+8^2=x^2
The zeros of 3^2+8^2=x^2 are x=sqrt(73),x=-sqrt(73)