What are the solutions to the equation 7x^2+5=12 ?

The solutions to the equation 7x^2+5=12 are x=1,x=-1

Find the zeros of 7x^2+5=12

The zeros of 7x^2+5=12 are x=1,x=-1

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7 x^{2} + 5 = 12

x = 1, x = - 1

Solution steps

7 x^{2} + 5 = 12

Move

5

to the right side

7 x^{2} = 7

Divide both sides by

7

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

\frac{3}{a + 1} \geq 3

4 g^{6} h^{6} - 9 j^{6} k^{6}

4 (x - 2)^{2} = 25

\frac{- 5}{5}

b + (- 6) + 13 = 25

What are the solutions to the equation 7x^2+5=12 ?
The solutions to the equation 7x^2+5=12 are x=1,x=-1
Find the zeros of 7x^2+5=12
The zeros of 7x^2+5=12 are x=1,x=-1