What is 10log_{10}(1/86400 10^{15/10}) ?

The solution to 10log_{10}(1/86400 10^{15/10}) is -10log_{10}(86400)+15

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simplify 10log_{10}(1/86400 10^{15/10})

simplify

10 lo g_{10} (\frac{1}{86400} 1 0^{\frac{15}{10}})

- 10 lo g_{10} (86400) + 15

Decimal

- 34.36513 \dots

Solution steps

10 lo g_{10} (\frac{1}{86400} \cdot 1 0^{\frac{15}{10}})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

10 lo g_{10} (\frac{1}{86400} \cdot 1 0^{\frac{15}{10}}) = 10 lo g_{10} (\frac{1}{86400}) + 10 lo g_{10} (1 0^{\frac{15}{10}})

= 10 lo g_{10} (\frac{1}{86400}) + 10 lo g_{10} (1 0^{\frac{15}{10}})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (1 0^{\frac{15}{10}}) = \frac{15}{10} lo g_{10} (10)

= 10 lo g_{10} (\frac{1}{86400}) + 10 \cdot \frac{15}{10} lo g_{10} (10)

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{1}{86400}) = lo g_{10} (1) - lo g_{10} (86400)

= 10 (lo g_{10} (1) - lo g_{10} (86400)) + 10 \cdot \frac{15}{10} lo g_{10} (10)

10 (lo g_{10} (1) - lo g_{10} (86400)) = - 10 lo g_{10} (86400)

= - 10 lo g_{10} (86400) + 10 \cdot \frac{15}{10} lo g_{10} (10)

10 \cdot \frac{15}{10} lo g_{10} (10) = 15

= - 10 lo g_{10} (86400) + 15

ln (x^{23}) + ln (y^{23})

\frac{1}{3} ln (\frac{x ( x + 1 )}{( y + 1 ) ^{3}})

22 ln (\frac{125}{11}) + 62 + 25 ln (30) + 15 ln (\frac{250}{3})

a pp ro x ima t e (\frac{4}{5} lo g_{2} (\frac{4}{5}))

ln (\frac{3 e ^{- n^{3} + n x}}{x})

What is 10log_{10}(1/86400 10^{15/10}) ?
The solution to 10log_{10}(1/86400 10^{15/10}) is -10log_{10}(86400)+15