What is ln|L+Vx|-ln|L+Vy| ?

The solution to ln|L+Vx|-ln|L+Vy| is ln((|L+Vx|)/(|L+Vy|))

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simplify ln|L+Vx|-ln|L+Vy|

simplify

ln ∣ L + V x ∣ - ln ∣ L + V y ∣

ln (\frac{∣ L + V x ∣}{∣ L + V y ∣})

Solution steps

ln ∣ L + V x ∣ - ln ∣ L + V y ∣

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln ∣ L + V x ∣ - ln ∣ L + V y ∣ = ln (\frac{∣ L + V x ∣}{∣ L + V y ∣})

= ln (\frac{∣ L + V x ∣}{∣ L + V y ∣})

(ln (1 - x^{2}) - ln (1 + x^{2}))^{2}

ln (cos (2 x) \frac{x + 4}{x})

ln (4) - ln (9 - 4)

- ln (5.4 - 3) + 2 ln (5.4 - 2) + c

ln (3) + 3 ln (2)

What is ln|L+Vx|-ln|L+Vy| ?
The solution to ln|L+Vx|-ln|L+Vy| is ln((|L+Vx|)/(|L+Vy|))