What are the solutions to the equation 6x^2+6x-12=0 ?

The solutions to the equation 6x^2+6x-12=0 are x=1,x=-2

Find the zeros of 6x^2+6x-12=0

The zeros of 6x^2+6x-12=0 are x=1,x=-2

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6 x^{2} + 6 x - 12 = 0

x = 1, x = - 2

Solution steps

6 x^{2} + 6 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 6 ( - 12 )}{2 \cdot 6}

6^{2} - 4 \cdot 6 (- 12) = 18

x_{1, 2} = \frac{- 6 \pm 18}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 6 + 18}{2 \cdot 6}, x_{2} = \frac{- 6 - 18}{2 \cdot 6}

x = \frac{- 6 + 18}{2 \cdot 6} : 1

x = \frac{- 6 - 18}{2 \cdot 6} : - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

0.2 x^{2} + 1 0^{- 4.7} x - 1 0^{- 4.7} = 0

1 b - b + 43 b = 16

(- b^{7}) (7 b^{4})

\frac{6 !}{( 6 - 3 ) ! 3 !}

3 x + 9 \leq 3

What are the solutions to the equation 6x^2+6x-12=0 ?
The solutions to the equation 6x^2+6x-12=0 are x=1,x=-2
Find the zeros of 6x^2+6x-12=0
The zeros of 6x^2+6x-12=0 are x=1,x=-2