What is sqrt(3x+9)<= 3 ?

The solution to sqrt(3x+9)<= 3 is -3<= x<= 0

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sqrt(3x+9)<= 3

3 x + 9 \leq 3

- 3 \leq x \leq 0

Interval Notation

[- 3, 0]

Solution steps

3 x + 9 \leq 3

Square both sides

(3 x + 9)^{2} \leq 3^{2}

Simplify

3 x + 9 \leq 9

3 x + 9 \leq 9 : x \leq 0

x \leq 0

Find singularity points

Find non-negative values for radicals:

x \geq - 3

Combine the intervals

x \leq 0 and x \geq - 3

Merge Overlapping Intervals

- 3 \leq x \leq 0

- 2 (x - 2) = 10

25 x^{2} - 30 x + 9 = 81

\frac{x}{9} + 7 = - 4

ln (x) \leq 1

4 x^{2} - 2 x - 12