What is 10log_{10}((320*10^{-7})/(10^{-12)}) ?

The solution to 10log_{10}((320*10^{-7})/(10^{-12)}) is 10(log_{10}(320*10^{-7})--12log_{10}(10))

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simplify 10log_{10}((320*10^{-7})/(10^{-12)})

simplify

10 lo g_{10} (\frac{320 \cdot 1 0 ^{- 7}}{1 0 ^{- 12}})

10 (lo g_{10} (320 \cdot 1 0^{- 7}) - - 12 lo g_{10} (10))

Decimal Notation

- 164.94850 \dots

Solution steps

10 lo g_{10} (\frac{320 \cdot 1 0 ^{- 7}}{1 0 ^{- 12}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{320 \cdot 1 0 ^{- 7}}{1 0 ^{- 12}}) = lo g_{10} (320 \cdot 1 0^{- 7}) - lo g_{10} (1 0^{- 12})

= 10 (lo g_{10} (1 0^{- 7} \cdot 320) - lo g_{10} (1 0^{- 12}))

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (1 0^{- 12}) = - 12 lo g_{10} (10)

= 10 (lo g_{10} (320 \cdot 1 0^{- 7}) - - 12 lo g_{10} (10))

2 ln (3) + ln (3^{2} + 2)

lo g_{a} (5 a x a^{4} x^{3} a)

ln ((8^{x} (3 x^{3} + 6)^{2})^{8} (9 x^{4} - 1)^{2})

10 ln (\frac{50}{1 0 ^{- 12}})

5.23 + lo g_{10} (\frac{1.76 \cdot 1 0 ^{- 3}}{0.00391})

What is 10log_{10}((320*10^{-7})/(10^{-12)}) ?
The solution to 10log_{10}((320*10^{-7})/(10^{-12)}) is 10(log_{10}(320*10^{-7})--12log_{10}(10))