What is 6x^3y^4-3sqrt(3)x^2y^2-3x^2y+3xy ?

The solution to 6x^3y^4-3sqrt(3)x^2y^2-3x^2y+3xy is 6x^3y^4-3^{3/2}x^2y^2-3x^2y+3xy

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6x^3y^4-3sqrt(3)x^2y^2-3x^2y+3xy

6 x^{3} y^{4} - 33 x^{2} y^{2} - 3 x^{2} y + 3 x y

6 x^{3} y^{4} - 3^{\frac{3}{2}} x^{2} y^{2} - 3 x^{2} y + 3 x y

Solution steps

6 x^{3} y^{4} - 33 x^{2} y^{2} - 3 x^{2} y + 3 x y

33 x^{2} y^{2} = 3^{\frac{3}{2}} x^{2} y^{2}

= 6 x^{3} y^{4} - 3^{\frac{3}{2}} x^{2} y^{2} - 3 x^{2} y + 3 x y

\frac{1}{8 ^{\frac{2}{3}}}

x^{3} + 9 x^{2} + 8 x - 60

(4 x - 1)^{2} = 20

0 = x^{2} + 2 x - 3

\frac{2 ( 1 )}{1 + 4}

What is 6x^3y^4-3sqrt(3)x^2y^2-3x^2y+3xy ?
The solution to 6x^3y^4-3sqrt(3)x^2y^2-3x^2y+3xy is 6x^3y^4-3^{3/2}x^2y^2-3x^2y+3xy