What is log_{10}(0.37x) ?

The solution to log_{10}(0.37x) is log_{10}(37)+log_{10}(x)-2

Popular >

simplify log_{10}(0.37x)

simplify

lo g_{10} (0.37 x)

lo g_{10} (37) + lo g_{10} (x) - 2

Solution steps

lo g_{10} (0.37 x)

Apply log rule:

lo g_{a} (x y) = lo g_{a} (x) + lo g_{a} (y)

lo g_{10} (0.37 x) = lo g_{10} (0.37) + lo g_{10} (x)

= lo g_{10} (0.37) + lo g_{10} (x)

lo g_{10} (0.37) = lo g_{10} (37) - 2

= lo g_{10} (37) - 2 + lo g_{10} (x)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{10} (37) + lo g_{10} (x) = lo g_{10} (37 x)

= lo g_{10} (37 x) - 2

Simplify

lo g_{10} (37 x) : lo g_{10} (37) + lo g_{10} (x)

= lo g_{10} (37) + lo g_{10} (x) - 2

ln (\frac{82.14}{500})

- lo g_{10} (5.5 \cdot 1 0^{- 3} \cdot 2)

6 lo g_{3} (y) - \frac{1}{4} lo g_{3} (z) + 5 lo g_{3} (x)

\frac{1}{2} ln ∣ y - 1 ∣ - \frac{1}{2} ln ∣ y + 1 ∣

lo g_{10} (2) - lo g_{10} (20.2)

What is log_{10}(0.37x) ?
The solution to log_{10}(0.37x) is log_{10}(37)+log_{10}(x)-2