What is ln(12.5)+ln(e^{1.6t}) ?

The solution to ln(12.5)+ln(e^{1.6t}) is ln(12.5e^{1.6t})

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simplify ln(12.5)+ln(e^{1.6t})

simplify

ln (12.5) + ln (e^{1.6 t})

ln (12.5 e^{1.6 t})

Solution steps

ln (12.5) + ln (e^{1.6 t})

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln (12.5) + ln (e^{1.6 t}) = ln (12.5 e^{1.6 t})

= ln (12.5 e^{1.6 t})

ln (x^{2}) + ln (2)

- \frac{1}{2} ln (3) + ln (\frac{1}{2}) - 1

ln (\frac{( x + 1 ^{2} )}{( x - 1 ^{4} )})

ln (\frac{ab}{c d})

1 ln (\frac{68}{75})

What is ln(12.5)+ln(e^{1.6t}) ?
The solution to ln(12.5)+ln(e^{1.6t}) is ln(12.5e^{1.6t})