What is ln(((x+1^2))/((x-1^4))) ?

The solution to ln(((x+1^2))/((x-1^4))) is ln(x+1)-ln(x-1)

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simplify ln(((x+1^2))/((x-1^4)))

simplify

ln (\frac{( x + 1 ^{2} )}{( x - 1 ^{4} )})

ln (x + 1) - ln (x - 1)

Solution steps

ln (\frac{( x + 1 ^{2} )}{( x - 1 ^{4} )})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{( x + 1 ^{2} )}{( x - 1 ^{4} )}) = ln ((x + 1^{2})) - ln ((x - 1^{4}))

= ln (x + 1^{2}) - ln (x - 1^{4})

Apply rule

1^{a} = 1

1^{2} = 1

= ln (x + 1) - ln (x - 1^{4})

Apply rule

1^{a} = 1

1^{4} = 1

= ln (x + 1) - ln (x - 1)

ln (\frac{ab}{c d})

1 ln (\frac{68}{75})

ln (e^{2} - e^{4} - 1) - ln (2 - 5)

ln (\frac{5.6}{0.25} \cdot 1 0^{- 7})

\frac{1}{2 \cdot ( 0.15 \cdot 1 0 ^{- 9} )} \cdot ln (\frac{1}{0.02})

What is ln(((x+1^2))/((x-1^4))) ?
The solution to ln(((x+1^2))/((x-1^4))) is ln(x+1)-ln(x-1)