What is ln((e^x-e^{-x})/2) ?

The solution to ln((e^x-e^{-x})/2) is ln(e^x-e^{-x})-ln(2)

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simplify ln((e^x-e^{-x})/2)

simplify

ln (\frac{e ^{x} - e ^{- x}}{2})

ln (e^{x} - e^{- x}) - ln (2)

Solution steps

ln (\frac{e ^{x} - e ^{- x}}{2})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{e ^{x} - e ^{- x}}{2}) = ln (e^{x} - e^{- x}) - ln (2)

= ln (e^{x} - e^{- x}) - ln (2)

ln (\frac{114}{132})

ln (\frac{7 x ^{5} - 8}{x ^{2}})

ln (\frac{c}{x})

ln (\frac{0.032785}{0.11756})

20 lo g_{10} (\frac{5 \cdot 1 0 ^{- 3}}{2}) + 4

What is ln((e^x-e^{-x})/2) ?
The solution to ln((e^x-e^{-x})/2) is ln(e^x-e^{-x})-ln(2)