What is 10log_{10}(i/(10^{12)i_{0}}) ?

The solution to 10log_{10}(i/(10^{12)i_{0}}) is 10(log_{10}(i)-log_{10}(10^{12}i_{0}))

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simplify 10log_{10}(i/(10^{12)i_{0}})

simplify

10 lo g_{10} (\frac{i}{1 0 ^{12} i _{0}})

10 (lo g_{10} (i) - lo g_{10} (1 0^{12} i_{0}))

Solution steps

10 lo g_{10} (\frac{i}{1 0 ^{12} i _{0}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{i}{1 0 ^{12} i _{0}}) = lo g_{10} (i) - lo g_{10} (1 0^{12} i_{0})

= 10 (lo g_{10} (i) - lo g_{10} (1 0^{12} i_{0}))

ln (\frac{2}{80})

600 ln (600) + 400 ln (400)

ln (\frac{sin ( y )}{cos ( x )})

ln (x \cdot e^{r})

2 - 4 \cdot (lo g_{e} (25) - lo g_{e} (13))

What is 10log_{10}(i/(10^{12)i_{0}}) ?
The solution to 10log_{10}(i/(10^{12)i_{0}}) is 10(log_{10}(i)-log_{10}(10^{12}i_{0}))